## 2017年2月19日 星期日

### 【Python】Codility in Python : Lesson 5 - Prefix Sums【MinAvgTwoSlice】

Prefix Sums 第四題：【MinAvgTwoSlice】
Find the minimal average of any slice containing at least two elements.
A non-empty zero-indexed array A consisting of N integers is given.
A pair of integers (P, Q), such that 0 ≤ P < Q < N,
is called a slice of array A (notice that the slice contains at least two elements).
The average of a slice (P, Q) is the sum of A[P] + A[P + 1] + ... + A[Q] divided by the length of the slice.
To be precise, the average equals (A[P] + A[P + 1] + ... + A[Q]) / (Q − P + 1).

For example, array A such that:

A = 4
A = 2
A = 2
A = 5
A = 1
A = 5
A = 8

contains the following example slices:

slice (1, 2), whose average is (2 + 2) / 2 = 2;
slice (3, 4), whose average is (5 + 1) / 2 = 3;
slice (1, 4), whose average is (2 + 2 + 5 + 1) / 4 = 2.5.

The goal is to find the starting position of a slice whose average is minimal.

Write a function:

def solution(A)

that, given a non-empty zero-indexed array A consisting of N integers,
returns the starting position of the slice with the minimal average.
If there is more than one slice with a minimal average,
you should return the smallest starting position of such a slice.

For example, given array A such that:

A = 4
A = 2
A = 2
A = 5
A = 1
A = 5
A = 8

the function should return 1, as explained above.

Correctness：100%、Performance：100%
```python import sys def solution(A): result = 0 length = len(A) valueList =  for i in range(length): valueList.append(valueList[i] + A[i]) minAvg = sys.float_info.max for i in range(length - 1): index1 = i + 1 index2 = i + 2 avg = (valueList[index1 + 1] - valueList[i]) / 2.0 if(avg < minAvg): minAvg = avg result = i if(i < length - 2): avg = (valueList[index2 + 1] - valueList[i]) / 3.0 if(avg < minAvg): minAvg = avg result = i return result ```